Base | Representation |
---|---|
bin | 11101110101010000011011… |
… | …111110000110011011111011 |
3 | 122012112220012201210011112200 |
4 | 131311100123332012123323 |
5 | 114144113002314103311 |
6 | 1143013515210041243 |
7 | 36431053606645236 |
oct | 3565203376063373 |
9 | 565486181704480 |
10 | 131203130222331 |
11 | 38894a31608722 |
12 | 12870066a19223 |
13 | 582952c51a14b |
14 | 24583a030a41d |
15 | 1027d63e9c556 |
hex | 77541bf866fb |
131203130222331 has 24 divisors (see below), whose sum is σ = 189943619752224. Its totient is φ = 87271334517120.
The previous prime is 131203130222321. The next prime is 131203130222407. The reversal of 131203130222331 is 133222031302131.
131203130222331 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 0 + 3 + 1 + 302 + 22 + 331 = 666.
It is not a de Polignac number, because 131203130222331 - 242 = 126805083711227 is a prime.
It is a super-3 number, since 3×1312031302223313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 131203130222295 and 131203130222304.
It is not an unprimeable number, because it can be changed into a prime (131203130222321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9134050 + ... + 18596696.
It is an arithmetic number, because the mean of its divisors is an integer number (7914317489676).
Almost surely, 2131203130222331 is an apocalyptic number.
131203130222331 is a deficient number, since it is larger than the sum of its proper divisors (58740489529893).
131203130222331 is a wasteful number, since it uses less digits than its factorization.
131203130222331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9466131 (or 9466128 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 131203130222331 its reverse (133222031302131), we get a palindrome (264425161524462).
The spelling of 131203130222331 in words is "one hundred thirty-one trillion, two hundred three billion, one hundred thirty million, two hundred twenty-two thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •