1312032304033 has 4 divisors (see below), whose sum is σ = 1431307968048. Its totient is φ = 1192756640020.

The previous prime is 1312032304013. The next prime is 1312032304061. The reversal of 1312032304033 is 3304032302131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1312032304033 - 2¹³ = 1312032295841 is a prime.

It is a super-2 number, since 2×1312032304033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312032303989 and 1312032304007.

It is not an unprimeable number, because it can be changed into a prime (1312032304013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59637831991 + ... + 59637832012.

It is an arithmetic number, because the mean of its divisors is an integer number (357826992012).

Almost surely, 2^{1312032304033} is an apocalyptic number.

It is an amenable number.

1312032304033 is a deficient number, since it is larger than the sum of its proper divisors (119275664015).

1312032304033 is a wasteful number, since it uses less digits than its factorization.

1312032304033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119275664014.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 1312032304033 its reverse (3304032302131), we get a palindrome (4616064606164).

The spelling of 1312032304033 in words is "one trillion, three hundred twelve billion, thirty-two million, three hundred four thousand, thirty-three".