Base | Representation |
---|---|
bin | 11101110101010000100001… |
… | …111110101010011010101011 |
3 | 122012112220110202110212210021 |
4 | 131311100201332222122223 |
5 | 114144113204121024003 |
6 | 1143013533210501311 |
7 | 36431056242555013 |
oct | 3565204176523253 |
9 | 565486422425707 |
10 | 131203231033003 |
11 | 38894a83503228 |
12 | 12870094734837 |
13 | 582954738592c |
14 | 24583ad86cc43 |
15 | 1027d6cc622bd |
hex | 775421faa6ab |
131203231033003 has 16 divisors (see below), whose sum is σ = 134650997659584. Its totient is φ = 127767280919040.
The previous prime is 131203231033001. The next prime is 131203231033033. The reversal of 131203231033003 is 300330132302131.
It is a cyclic number.
It is not a de Polignac number, because 131203231033003 - 21 = 131203231033001 is a prime.
It is a super-2 number, since 2×1312032310330032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131203231033001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 525514426 + ... + 525764032.
It is an arithmetic number, because the mean of its divisors is an integer number (8415687353724).
Almost surely, 2131203231033003 is an apocalyptic number.
131203231033003 is a deficient number, since it is larger than the sum of its proper divisors (3447766626581).
131203231033003 is a wasteful number, since it uses less digits than its factorization.
131203231033003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 273222.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 131203231033003 its reverse (300330132302131), we get a palindrome (431533363335134).
The spelling of 131203231033003 in words is "one hundred thirty-one trillion, two hundred three billion, two hundred thirty-one million, thirty-three thousand, three".
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