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13120414400041 = 132759633657239
BaseRepresentation
bin1011111011101101010110…
…1000111011111000101001
31201110022002020102211202121
42332323111220323320221
53204431102041300131
643523233555031241
72522630046202234
oct276732550737051
951408066384677
1013120414400041
1141a9377975793
12157a9a829b521
137423329865c0
1433506240041b
1517b45abe7911
hexbeed5a3be29

13120414400041 has 8 divisors (see below), whose sum is σ = 14129732111040. Its totient is φ = 12111104555472.

The previous prime is 13120414400003. The next prime is 13120414400101. The reversal of 13120414400041 is 14000441402131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13120414400041 - 213 = 13120414391849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13120414399979 and 13120414400015.

It is not an unprimeable number, because it can be changed into a prime (13120414406041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1758900 + ... + 5416138.

It is an arithmetic number, because the mean of its divisors is an integer number (1766216513880).

Almost surely, 213120414400041 is an apocalyptic number.

It is an amenable number.

13120414400041 is a deficient number, since it is larger than the sum of its proper divisors (1009317710999).

13120414400041 is a wasteful number, since it uses less digits than its factorization.

13120414400041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3933215.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13120414400041 its reverse (14000441402131), we get a palindrome (27120855802172).

The spelling of 13120414400041 in words is "thirteen trillion, one hundred twenty billion, four hundred fourteen million, four hundred thousand, forty-one".

Divisors: 1 13 275963 3587519 3657239 47544107 1009262646157 13120414400041