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13120421121403 = 312632935492407
BaseRepresentation
bin1011111011101101011000…
…0010100100110101111011
31201110022002201002022201221
42332323112002210311323
53204431110301341103
643523234355052511
72522630160265111
oct276732602446573
951408081068657
1013120421121403
1141a9380746632
12157a9aa5a1137
1374233419aa3b
1433506326dab1
1517b45b5c41bd
hexbeed60a4d7b

13120421121403 has 16 divisors (see below), whose sum is σ = 13641559658496. Its totient is φ = 12605730858720.

The previous prime is 13120421121397. The next prime is 13120421121407. The reversal of 13120421121403 is 30412112402131.

It is a cyclic number.

It is not a de Polignac number, because 13120421121403 - 225 = 13120387566971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13120421121407) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 357375 + ... + 5135032.

It is an arithmetic number, because the mean of its divisors is an integer number (852597478656).

Almost surely, 213120421121403 is an apocalyptic number.

13120421121403 is a deficient number, since it is larger than the sum of its proper divisors (521138537093).

13120421121403 is a wasteful number, since it uses less digits than its factorization.

13120421121403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5492994.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13120421121403 its reverse (30412112402131), we get a palindrome (43532533523534).

The spelling of 13120421121403 in words is "thirteen trillion, one hundred twenty billion, four hundred twenty-one million, one hundred twenty-one thousand, four hundred three".

Divisors: 1 31 263 293 8153 9083 77059 2388829 5492407 170264617 1444503041 1609275251 44779594271 49887532781 423239391013 13120421121403