Base | Representation |
---|---|
bin | 1011111011101101011011… |
… | …0000010100010000100101 |
3 | 1201110022010112122111212212 |
4 | 2332323112300110100211 |
5 | 3204431121334041401 |
6 | 43523235504053205 |
7 | 2522630364225320 |
oct | 276732660242045 |
9 | 51408115574785 |
10 | 13120433112101 |
11 | 41a93874963a7 |
12 | 157a9b2604205 |
13 | 742336808723 |
14 | 335064ab17b7 |
15 | 17b45c691dbb |
hex | beed6c14425 |
13120433112101 has 16 divisors (see below), whose sum is σ = 15249190010880. Its totient is φ = 11055285054000.
The previous prime is 13120433112067. The next prime is 13120433112103. The reversal of 13120433112101 is 10121133402131.
13120433112101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13120433112101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120433112103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27330200 + ... + 27806126.
It is an arithmetic number, because the mean of its divisors is an integer number (953074375680).
Almost surely, 213120433112101 is an apocalyptic number.
It is an amenable number.
13120433112101 is a deficient number, since it is larger than the sum of its proper divisors (2128756898779).
13120433112101 is an equidigital number, since it uses as much as digits as its factorization.
13120433112101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 542744.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 13120433112101 its reverse (10121133402131), we get a palindrome (23241566514232).
The spelling of 13120433112101 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-three million, one hundred twelve thousand, one hundred one".
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