Base | Representation |
---|---|
bin | 10011000101111011111… |
… | …010110010100001010111 |
3 | 11122102121121022210001111 |
4 | 103011323322302201113 |
5 | 132444031233043020 |
6 | 2442424505035451 |
7 | 163535450164462 |
oct | 23057372624127 |
9 | 4572547283044 |
10 | 1312044034135 |
11 | 46648671a30a |
12 | 192348a85b87 |
13 | 96957408a63 |
14 | 47708d8a2d9 |
15 | 241e1492d5a |
hex | 1317beb2857 |
1312044034135 has 16 divisors (see below), whose sum is σ = 1659856865760. Its totient is φ = 992868416640.
The previous prime is 1312044034109. The next prime is 1312044034157. The reversal of 1312044034135 is 5314304402131.
It is a de Polignac number, because none of the positive numbers 2k-1312044034135 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312044034097 and 1312044034106.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10512996 + ... + 10637065.
It is an arithmetic number, because the mean of its divisors is an integer number (103741054110).
Almost surely, 21312044034135 is an apocalyptic number.
1312044034135 is a deficient number, since it is larger than the sum of its proper divisors (347812831625).
1312044034135 is a wasteful number, since it uses less digits than its factorization.
1312044034135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21150738.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1312044034135 its reverse (5314304402131), we get a palindrome (6626348436266).
The spelling of 1312044034135 in words is "one trillion, three hundred twelve billion, forty-four million, thirty-four thousand, one hundred thirty-five".
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