Base | Representation |
---|---|
bin | 1011111011101101101011… |
… | …0100011010010100100000 |
3 | 1201110022022021221112101000 |
4 | 2332323122310122110200 |
5 | 3204431241312404433 |
6 | 43523250341312000 |
7 | 2522632152611406 |
oct | 276733264322440 |
9 | 51408267845330 |
10 | 13120501294368 |
11 | 41a9411a25786 |
12 | 157aa11405600 |
13 | 74234798ba70 |
14 | 33506db7d476 |
15 | 17b46365e113 |
hex | beedad1a520 |
13120501294368 has 384 divisors, whose sum is σ = 43405644441600. Its totient is φ = 3825454887936.
The previous prime is 13120501294363. The next prime is 13120501294469. The reversal of 13120501294368 is 86349210502131.
13120501294368 is a `hidden beast` number, since 1 + 3 + 1 + 20 + 501 + 2 + 94 + 36 + 8 = 666.
It is not an unprimeable number, because it can be changed into a prime (13120501294363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27404623 + ... + 27879281.
It is an arithmetic number, because the mean of its divisors is an integer number (113035532400).
Almost surely, 213120501294368 is an apocalyptic number.
13120501294368 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13120501294368, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21702822220800).
13120501294368 is an abundant number, since it is smaller than the sum of its proper divisors (30285143147232).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120501294368 is a wasteful number, since it uses less digits than its factorization.
13120501294368 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 474821 (or 474807 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 45.
Adding to 13120501294368 its reverse (86349210502131), we get a palindrome (99469711796499).
The spelling of 13120501294368 in words is "thirteen trillion, one hundred twenty billion, five hundred one million, two hundred ninety-four thousand, three hundred sixty-eight".
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