Search a number
-
+
13121001223303 = 60597721652639
BaseRepresentation
bin1011111011101111100010…
…0111011111010010000111
31201110100121010122112221111
42332323320213133102013
53204433302303121203
643523412120425451
72522650433131231
oct276737047372207
951410533575844
1013121001223303
1141a9649143796
12157ab30918287
137423c741a6bc
143350ba317251
1517b4924b126d
hexbeef89df487

13121001223303 has 4 divisors (see below), whose sum is σ = 13121023481920. Its totient is φ = 13120978964688.

The previous prime is 13121001223289. The next prime is 13121001223339. The reversal of 13121001223303 is 30332210012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121001223303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121001223903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10220343 + ... + 11432296.

It is an arithmetic number, because the mean of its divisors is an integer number (3280255870480).

Almost surely, 213121001223303 is an apocalyptic number.

13121001223303 is a deficient number, since it is larger than the sum of its proper divisors (22258617).

13121001223303 is an equidigital number, since it uses as much as digits as its factorization.

13121001223303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22258616.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13121001223303 its reverse (30332210012131), we get a palindrome (43453211235434).

The spelling of 13121001223303 in words is "thirteen trillion, one hundred twenty-one billion, one million, two hundred twenty-three thousand, three hundred three".

Divisors: 1 605977 21652639 13121001223303