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13121012221111 = 43753299888287
BaseRepresentation
bin1011111011101111100101…
…0001011100010010110111
31201110100121220100022002201
42332323321101130102313
53204433313112033421
643523413152245331
72522650625454634
oct276737121342267
951410556308081
1013121012221111
1141a9654375593
12157ab34540847
137423c979b492
143350bb97b18b
1517b493434b91
hexbeef945c4b7

13121012221111 has 4 divisors (see below), whose sum is σ = 13121312153152. Its totient is φ = 13120712289072.

The previous prime is 13121012221103. The next prime is 13121012221159. The reversal of 13121012221111 is 11112221012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13121012221111 - 23 = 13121012221103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121012221511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149900391 + ... + 149987896.

It is an arithmetic number, because the mean of its divisors is an integer number (3280328038288).

Almost surely, 213121012221111 is an apocalyptic number.

13121012221111 is a deficient number, since it is larger than the sum of its proper divisors (299932041).

13121012221111 is an equidigital number, since it uses as much as digits as its factorization.

13121012221111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 299932040.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 13121012221111 its reverse (11112221012131), we get a palindrome (24233233233242).

The spelling of 13121012221111 in words is "thirteen trillion, one hundred twenty-one billion, twelve million, two hundred twenty-one thousand, one hundred eleven".

Divisors: 1 43753 299888287 13121012221111