13121013020433 has 4 divisors (see below), whose sum is σ = 17494684027248. Its totient is φ = 8747342013620.

The previous prime is 13121013020327. The next prime is 13121013020441. The reversal of 13121013020433 is 33402031012131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13121013020433 - 2⁹ = 13121013019921 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13121013120433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186835503403 + ... + 2186835503408.

It is an arithmetic number, because the mean of its divisors is an integer number (4373671006812).

Almost surely, 2^{13121013020433} is an apocalyptic number.

It is an amenable number.

13121013020433 is a deficient number, since it is larger than the sum of its proper divisors (4373671006815).

13121013020433 is an equidigital number, since it uses as much as digits as its factorization.

13121013020433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4373671006814.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 13121013020433 its reverse (33402031012131), we get a palindrome (46523044032564).

The spelling of 13121013020433 in words is "thirteen trillion, one hundred twenty-one billion, thirteen million, twenty thousand, four hundred thirty-three".