Base | Representation |
---|---|
bin | 11101110101010110111110… |
… | …101011111011111010011111 |
3 | 122012120120100022100122110220 |
4 | 131311112332223323322133 |
5 | 114144221344202123033 |
6 | 1143021040233532423 |
7 | 36431422650356340 |
oct | 3565267653737237 |
9 | 565516308318426 |
10 | 131210155114143 |
11 | 38897a06a13936 |
12 | 128714a7574113 |
13 | 582a0aba29c71 |
14 | 24588692a60c7 |
15 | 1028125a81bb3 |
hex | 7755beafbe9f |
131210155114143 has 16 divisors (see below), whose sum is σ = 211700418336000. Its totient is φ = 70566806111616.
The previous prime is 131210155114139. The next prime is 131210155114163. The reversal of 131210155114143 is 341411551012131.
It is not a de Polignac number, because 131210155114143 - 22 = 131210155114139 is a prime.
It is a super-2 number, since 2×1312101551141432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131210155114123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 183767723893 + ... + 183767724606.
It is an arithmetic number, because the mean of its divisors is an integer number (13231276146000).
Almost surely, 2131210155114143 is an apocalyptic number.
131210155114143 is a deficient number, since it is larger than the sum of its proper divisors (80490263221857).
131210155114143 is a wasteful number, since it uses less digits than its factorization.
131210155114143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 367535448526.
The product of its (nonzero) digits is 7200, while the sum is 33.
The spelling of 131210155114143 in words is "one hundred thirty-one trillion, two hundred ten billion, one hundred fifty-five million, one hundred fourteen thousand, one hundred forty-three".
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