Base | Representation |
---|---|
bin | 1011111011101111100111… |
… | …0100000101000100001010 |
3 | 1201110100122112102121100222 |
4 | 2332323321310011010022 |
5 | 3204433322423113002 |
6 | 43523414115030042 |
7 | 2522651065602626 |
oct | 276737164050412 |
9 | 51410575377328 |
10 | 13121021301002 |
11 | 41a965950742a |
12 | 157ab3759b322 |
13 | 7423cb62a2b4 |
14 | 3350bcc62186 |
15 | 17b49412a1a2 |
hex | beef9d0510a |
13121021301002 has 4 divisors (see below), whose sum is σ = 19681531951506. Its totient is φ = 6560510650500.
The previous prime is 13121021301001. The next prime is 13121021301067. The reversal of 13121021301002 is 20010312012131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11734399653601 + 1386621647401 = 3425551^2 + 1177549^2 .
It is a super-2 number, since 2×131210213010022 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13121021301001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280255325249 + ... + 3280255325252.
Almost surely, 213121021301002 is an apocalyptic number.
13121021301002 is a deficient number, since it is larger than the sum of its proper divisors (6560510650504).
13121021301002 is an equidigital number, since it uses as much as digits as its factorization.
13121021301002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6560510650503.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13121021301002 its reverse (20010312012131), we get a palindrome (33131333313133).
The spelling of 13121021301002 in words is "thirteen trillion, one hundred twenty-one billion, twenty-one million, three hundred one thousand, two".
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