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131210214139 = 900891456451
BaseRepresentation
bin111101000110010111…
…1001111101011111011
3110112200021011111022201
41322030233033223323
54122204303323024
6140135510131031
712323340263314
oct1721457175373
9415607144281
10131210214139
1150711821a04
122151a050a77
13c4b0834184
1464ca0d760b
15362e21a744
hex1e8cbcfafb

131210214139 has 4 divisors (see below), whose sum is σ = 131211760680. Its totient is φ = 131208667600.

The previous prime is 131210214127. The next prime is 131210214169. The reversal of 131210214139 is 931412012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131210214139 - 225 = 131176659707 is a prime.

It is a super-3 number, since 3×1312102141393 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131210214119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638137 + ... + 818314.

It is an arithmetic number, because the mean of its divisors is an integer number (32802940170).

Almost surely, 2131210214139 is an apocalyptic number.

131210214139 is a deficient number, since it is larger than the sum of its proper divisors (1546541).

131210214139 is an equidigital number, since it uses as much as digits as its factorization.

131210214139 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1546540.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 131210214139 in words is "one hundred thirty-one billion, two hundred ten million, two hundred fourteen thousand, one hundred thirty-nine".

Divisors: 1 90089 1456451 131210214139