Base | Representation |
---|---|
bin | 111101000110010111… |
… | …1001111101011111100 |
3 | 110112200021011111022202 |
4 | 1322030233033223330 |
5 | 4122204303323030 |
6 | 140135510131032 |
7 | 12323340263315 |
oct | 1721457175374 |
9 | 415607144282 |
10 | 131210214140 |
11 | 50711821a05 |
12 | 2151a050a78 |
13 | c4b0834185 |
14 | 64ca0d760c |
15 | 362e21a745 |
hex | 1e8cbcfafc |
131210214140 has 24 divisors (see below), whose sum is σ = 278382087312. Its totient is φ = 51943011840.
The previous prime is 131210214127. The next prime is 131210214169. The reversal of 131210214140 is 41412012131.
It is a super-2 number, since 2×1312102141402 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33815126 + ... + 33819005.
It is an arithmetic number, because the mean of its divisors is an integer number (11599253638).
Almost surely, 2131210214140 is an apocalyptic number.
131210214140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131210214140 is an abundant number, since it is smaller than the sum of its proper divisors (147171873172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131210214140 is a wasteful number, since it uses less digits than its factorization.
131210214140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67634237 (or 67634235 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 131210214140 its reverse (41412012131), we get a palindrome (172622226271).
The spelling of 131210214140 in words is "one hundred thirty-one billion, two hundred ten million, two hundred fourteen thousand, one hundred forty".
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