13121052341443 has 4 divisors (see below), whose sum is σ = 13129341068448. Its totient is φ = 13112763614440.

The previous prime is 13121052341413. The next prime is 13121052341459. The reversal of 13121052341443 is 34414325012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13121052341443 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121052341399 and 13121052341408.

It is not an unprimeable number, because it can be changed into a prime (13121052341413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4144361128 + ... + 4144364293.

It is an arithmetic number, because the mean of its divisors is an integer number (3282335267112).

Almost surely, 2^{13121052341443} is an apocalyptic number.

13121052341443 is a deficient number, since it is larger than the sum of its proper divisors (8288727005).

13121052341443 is an equidigital number, since it uses as much as digits as its factorization.

13121052341443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8288727004.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 13121052341443 its reverse (34414325012131), we get a palindrome (47535377353574).

The spelling of 13121052341443 in words is "thirteen trillion, one hundred twenty-one billion, fifty-two million, three hundred forty-one thousand, four hundred forty-three".