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13121057451 = 312734438471
BaseRepresentation
bin11000011100001001…
…10111001010101011
31020212102120210001210
430032010313022223
5203332442314301
610005553444203
7643103101545
oct141604671253
936772523053
1013121057451
115623549737
122662270663
1313114a9028
148c687c695
1551bdb5ad6
hex30e1372ab

13121057451 has 8 divisors (see below), whose sum is σ = 17632497664. Its totient is φ = 8678494440.

The previous prime is 13121057437. The next prime is 13121057461. The reversal of 13121057451 is 15475012131.

13121057451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-13121057451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13121057461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17218855 + ... + 17219616.

It is an arithmetic number, because the mean of its divisors is an integer number (2204062208).

Almost surely, 213121057451 is an apocalyptic number.

13121057451 is a deficient number, since it is larger than the sum of its proper divisors (4511440213).

13121057451 is a wasteful number, since it uses less digits than its factorization.

13121057451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34438601.

The product of its (nonzero) digits is 4200, while the sum is 30.

Adding to 13121057451 its reverse (15475012131), we get a palindrome (28596069582).

The spelling of 13121057451 in words is "thirteen billion, one hundred twenty-one million, fifty-seven thousand, four hundred fifty-one".

Divisors: 1 3 127 381 34438471 103315413 4373685817 13121057451