Base | Representation |
---|---|
bin | 111101000110011001… |
… | …0010010110010110101 |
3 | 110112200022200002120022 |
4 | 1322030302102302311 |
5 | 4122210004411201 |
6 | 140135535214525 |
7 | 12323350132244 |
oct | 1721462226265 |
9 | 415608602508 |
10 | 131211013301 |
11 | 50712218375 |
12 | 2151a377445 |
13 | c4b0a53b54 |
14 | 64ca26495b |
15 | 362e32741b |
hex | 1e8cc92cb5 |
131211013301 has 4 divisors (see below), whose sum is σ = 131212136832. Its totient is φ = 131209889772.
The previous prime is 131211013279. The next prime is 131211013303. The reversal of 131211013301 is 103310112131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 131211013301 - 218 = 131210751157 is a prime.
It is a super-2 number, since 2×1312110133012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131211013301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131211013303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363191 + ... + 627956.
It is an arithmetic number, because the mean of its divisors is an integer number (32803034208).
Almost surely, 2131211013301 is an apocalyptic number.
It is an amenable number.
131211013301 is a deficient number, since it is larger than the sum of its proper divisors (1123531).
131211013301 is an equidigital number, since it uses as much as digits as its factorization.
131211013301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1123530.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 131211013301 its reverse (103310112131), we get a palindrome (234521125432).
The spelling of 131211013301 in words is "one hundred thirty-one billion, two hundred eleven million, thirteen thousand, three hundred one".
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