Base | Representation |
---|---|
bin | 111101000110011001… |
… | …0010010111111100011 |
3 | 110112200022200010200110 |
4 | 1322030302102333203 |
5 | 4122210004422430 |
6 | 140135535222403 |
7 | 12323350134516 |
oct | 1721462227743 |
9 | 415608603613 |
10 | 131211014115 |
11 | 50712218a45 |
12 | 2151a377a03 |
13 | c4b0a5432c |
14 | 64ca264d7d |
15 | 362e3277b0 |
hex | 1e8cc92fe3 |
131211014115 has 32 divisors (see below), whose sum is σ = 213153822720. Its totient is φ = 68907953664.
The previous prime is 131211014113. The next prime is 131211014147. The reversal of 131211014115 is 511410112131.
It is not a de Polignac number, because 131211014115 - 21 = 131211014113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131211014091 and 131211014100.
It is not an unprimeable number, because it can be changed into a prime (131211014111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2708587 + ... + 2756603.
It is an arithmetic number, because the mean of its divisors is an integer number (6661056960).
Almost surely, 2131211014115 is an apocalyptic number.
131211014115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131211014115 is a deficient number, since it is larger than the sum of its proper divisors (81942808605).
131211014115 is a wasteful number, since it uses less digits than its factorization.
131211014115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50811.
The product of its (nonzero) digits is 120, while the sum is 21.
Adding to 131211014115 its reverse (511410112131), we get a palindrome (642621126246).
The spelling of 131211014115 in words is "one hundred thirty-one billion, two hundred eleven million, fourteen thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •