13121113 has 4 divisors (see below), whose sum is σ = 13141008. Its totient is φ = 13101220.

The previous prime is 13121099. The next prime is 13121117. The reversal of 13121113 is 31112131.

13121113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13121113 - 2¹⁷ = 12990041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121093 and 13121102.

It is not an unprimeable number, because it can be changed into a prime (13121117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8923 + ... + 10288.

It is an arithmetic number, because the mean of its divisors is an integer number (3285252).

Almost surely, 2^13121113 is an apocalyptic number.

It is an amenable number.

13121113 is a deficient number, since it is larger than the sum of its proper divisors (19895).

13121113 is an equidigital number, since it uses as much as digits as its factorization.

13121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19894.

The product of its digits is 18, while the sum is 13.

The square root of 13121113 is about 3622.3076898574. The cubic root of 13121113 is about 235.8614107783.

Adding to 13121113 its reverse (31112131), we get a palindrome (44233244).

The spelling of 13121113 in words is "thirteen million, one hundred twenty-one thousand, one hundred thirteen".