Search a number
-
+
13121113565 = 57374888959
BaseRepresentation
bin11000011100001010…
…00100110111011101
31020212102200122001002
430032011010313131
5203333001113230
610005555000045
7643103424260
oct141605046735
936772618032
1013121113565
11562358790a
122662299025
1313114c8731
148c6894cd7
1551bdc7545
hex30e144ddd

13121113565 has 8 divisors (see below), whose sum is σ = 17994670080. Its totient is φ = 8997334992.

The previous prime is 13121113549. The next prime is 13121113591. The reversal of 13121113565 is 56531112131.

13121113565 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13121113565 - 24 = 13121113549 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 187444445 + ... + 187444514.

It is an arithmetic number, because the mean of its divisors is an integer number (2249333760).

Almost surely, 213121113565 is an apocalyptic number.

It is an amenable number.

13121113565 is a deficient number, since it is larger than the sum of its proper divisors (4873556515).

13121113565 is an equidigital number, since it uses as much as digits as its factorization.

13121113565 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 374888971.

The product of its digits is 2700, while the sum is 29.

Adding to 13121113565 its reverse (56531112131), we get a palindrome (69652225696).

The spelling of 13121113565 in words is "thirteen billion, one hundred twenty-one million, one hundred thirteen thousand, five hundred sixty-five".

Divisors: 1 5 7 35 374888959 1874444795 2624222713 13121113565