Base | Representation |
---|---|
bin | 11101110101010111111101… |
… | …101100100011101000010111 |
3 | 122012120200001222112021111102 |
4 | 131311113331230203220113 |
5 | 114144231030313211211 |
6 | 1143021333155500315 |
7 | 36431461104661160 |
oct | 3565277554435027 |
9 | 565520058467442 |
10 | 131211212241431 |
11 | 388983a9706253 |
12 | 128717415b769b |
13 | 582a219a4967a |
14 | 2458929844767 |
15 | 1028188799a3b |
hex | 7755fdb23a17 |
131211212241431 has 8 divisors (see below), whose sum is σ = 149961035921184. Its totient is φ = 112462729758720.
The previous prime is 131211212241419. The next prime is 131211212241451. The reversal of 131211212241431 is 134142212112131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131211212241431 - 226 = 131211145132567 is a prime.
It is a super-2 number, since 2×1312112122414312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131211212241394 and 131211212241403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131211212241401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 335089610 + ... + 335480951.
It is an arithmetic number, because the mean of its divisors is an integer number (18745129490148).
Almost surely, 2131211212241431 is an apocalyptic number.
131211212241431 is a deficient number, since it is larger than the sum of its proper divisors (18749823679753).
131211212241431 is an equidigital number, since it uses as much as digits as its factorization.
131211212241431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 670598521.
The product of its digits is 2304, while the sum is 29.
Adding to 131211212241431 its reverse (134142212112131), we get a palindrome (265353424353562).
The spelling of 131211212241431 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred twelve million, two hundred forty-one thousand, four hundred thirty-one".
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