Base | Representation |
---|---|
bin | 1011111011101111111111… |
… | …0001100111110100010011 |
3 | 1201110100220111122002221010 |
4 | 2332323333301213310103 |
5 | 3204434024024221321 |
6 | 43523432050502003 |
7 | 2522653422005052 |
oct | 276737761476423 |
9 | 51410814562833 |
10 | 13121121320211 |
11 | 41a96aaa11333 |
12 | 157ab64b94903 |
13 | 742416279768 |
14 | 3350cc25a399 |
15 | 17b49ccd5676 |
hex | beeffc67d13 |
13121121320211 has 4 divisors (see below), whose sum is σ = 17494828426952. Its totient is φ = 8747414213472.
The previous prime is 13121121320191. The next prime is 13121121320261. The reversal of 13121121320211 is 11202312112131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13121121320211 - 233 = 13112531385619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13121121320261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186853553366 + ... + 2186853553371.
It is an arithmetic number, because the mean of its divisors is an integer number (4373707106738).
Almost surely, 213121121320211 is an apocalyptic number.
13121121320211 is a deficient number, since it is larger than the sum of its proper divisors (4373707106741).
13121121320211 is an equidigital number, since it uses as much as digits as its factorization.
13121121320211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4373707106740.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 13121121320211 its reverse (11202312112131), we get a palindrome (24323433432342).
The spelling of 13121121320211 in words is "thirteen trillion, one hundred twenty-one billion, one hundred twenty-one million, three hundred twenty thousand, two hundred eleven".
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