Base | Representation |
---|---|
bin | 1011111011101111111111… |
… | …0001100111110011111111 |
3 | 1201110100220111122002220101 |
4 | 2332323333301213303333 |
5 | 3204434024024221231 |
6 | 43523432050501531 |
7 | 2522653422005023 |
oct | 276737761476377 |
9 | 51410814562811 |
10 | 13121121320191 |
11 | 41a96aaa11315 |
12 | 157ab64b948a7 |
13 | 742416279751 |
14 | 3350cc25a383 |
15 | 17b49ccd5661 |
hex | beeffc67cff |
13121121320191 has 2 divisors, whose sum is σ = 13121121320192. Its totient is φ = 13121121320190.
The previous prime is 13121121320173. The next prime is 13121121320261. The reversal of 13121121320191 is 19102312112131.
It is a weak prime.
It is an emirp because it is prime and its reverse (19102312112131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13121121320191 - 223 = 13121112931583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121121320161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560560660095 + 6560560660096.
It is an arithmetic number, because the mean of its divisors is an integer number (6560560660096).
Almost surely, 213121121320191 is an apocalyptic number.
13121121320191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121121320191 is an equidigital number, since it uses as much as digits as its factorization.
13121121320191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
The spelling of 13121121320191 in words is "thirteen trillion, one hundred twenty-one billion, one hundred twenty-one million, three hundred twenty thousand, one hundred ninety-one".
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