Base | Representation |
---|---|
bin | 11101110101010111111110… |
… | …010011010100000100111101 |
3 | 122012120200002200122110021101 |
4 | 131311113332103110010331 |
5 | 114144231040413320331 |
6 | 1143021334201333101 |
7 | 36431461260224665 |
oct | 3565277623240475 |
9 | 565520080573241 |
10 | 131211222401341 |
11 | 38898404415575 |
12 | 12871744a97191 |
13 | 582a21bb95c54 |
14 | 245892ad2b1a5 |
15 | 1028189605061 |
hex | 7755fe4d413d |
131211222401341 has 16 divisors (see below), whose sum is σ = 132292552250880. Its totient is φ = 130133441496960.
The previous prime is 131211222401197. The next prime is 131211222401401. The reversal of 131211222401341 is 143104222112131.
It is a cyclic number.
It is not a de Polignac number, because 131211222401341 - 231 = 131209074917693 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131211222401641) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2206276236 + ... + 2206335706.
It is an arithmetic number, because the mean of its divisors is an integer number (8268284515680).
Almost surely, 2131211222401341 is an apocalyptic number.
It is an amenable number.
131211222401341 is a deficient number, since it is larger than the sum of its proper divisors (1081329849539).
131211222401341 is a wasteful number, since it uses less digits than its factorization.
131211222401341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89004.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 131211222401341 its reverse (143104222112131), we get a palindrome (274315444513472).
The spelling of 131211222401341 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred twenty-two million, four hundred one thousand, three hundred forty-one".
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