131211244120223 has 4 divisors (see below), whose sum is σ = 131576735051280. Its totient is φ = 130845753189168.

The previous prime is 131211244120211. The next prime is 131211244120283. The reversal of 131211244120223 is 322021442112131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131211244120223 - 2⁴ = 131211244120207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211244120283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182745464990 + ... + 182745465707.

It is an arithmetic number, because the mean of its divisors is an integer number (32894183762820).

Almost surely, 2^{131211244120223} is an apocalyptic number.

131211244120223 is a deficient number, since it is larger than the sum of its proper divisors (365490931057).

131211244120223 is an equidigital number, since it uses as much as digits as its factorization.

131211244120223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 365490931056.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131211244120223 its reverse (322021442112131), we get a palindrome (453232686232354).

The spelling of 131211244120223 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred forty-four million, one hundred twenty thousand, two hundred twenty-three".