131211244121143 has 8 divisors (see below), whose sum is σ = 131297199096960. Its totient is φ = 131125291444920.

The previous prime is 131211244120921. The next prime is 131211244121149. The reversal of 131211244121143 is 341121442112131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131211244121143 - 2²¹ = 131211242023991 is a prime.

It is a super-3 number, since 3×131211244121143³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211244121149) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 122144496 + ... + 123214042.

It is an arithmetic number, because the mean of its divisors is an integer number (16412149887120).

Almost surely, 2^{131211244121143} is an apocalyptic number.

131211244121143 is a deficient number, since it is larger than the sum of its proper divisors (85954975817).

131211244121143 is a wasteful number, since it uses less digits than its factorization.

131211244121143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1149797.

The product of its digits is 4608, while the sum is 31.

Adding to 131211244121143 its reverse (341121442112131), we get a palindrome (472332686233274).

The spelling of 131211244121143 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred forty-four million, one hundred twenty-one thousand, one hundred forty-three".