13121133000229 has 4 divisors (see below), whose sum is σ = 13141043673120. Its totient is φ = 13101222327340.

The previous prime is 13121133000197. The next prime is 13121133000263. The reversal of 13121133000229 is 92200033112131.

13121133000229 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13121133000229 - 2⁵ = 13121133000197 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121133000197 and 13121133000206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121133000529) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9955335457 + ... + 9955336774.

It is an arithmetic number, because the mean of its divisors is an integer number (3285260918280).

Almost surely, 2^{13121133000229} is an apocalyptic number.

It is an amenable number.

13121133000229 is a deficient number, since it is larger than the sum of its proper divisors (19910672891).

13121133000229 is an equidigital number, since it uses as much as digits as its factorization.

13121133000229 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19910672890.

The product of its (nonzero) digits is 1944, while the sum is 28.

The spelling of 13121133000229 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-three million, two hundred twenty-nine", and thus it is an aban number.