Base | Representation |
---|---|
bin | 11101110101011000001011… |
… | …010001110110001001010010 |
3 | 122012120200122212022201200022 |
4 | 131311120023101312021102 |
5 | 114144232012132323102 |
6 | 1143021411540023442 |
7 | 36431466542631305 |
oct | 3565301321661122 |
9 | 565520585281608 |
10 | 131211440120402 |
11 | 38898506300084 |
12 | 128717a5991b82 |
13 | 582a2550153b5 |
14 | 245894bc02b3c |
15 | 102819d7ae5a2 |
hex | 77560b476252 |
131211440120402 has 4 divisors (see below), whose sum is σ = 196817160180606. Its totient is φ = 65605720060200.
The previous prime is 131211440120399. The next prime is 131211440120417. The reversal of 131211440120402 is 204021044112131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 126114000542401 + 5097439578001 = 11230049^2 + 2257751^2 .
It is a super-2 number, since 2×1312114401204022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32802860030099 + ... + 32802860030102.
Almost surely, 2131211440120402 is an apocalyptic number.
131211440120402 is a deficient number, since it is larger than the sum of its proper divisors (65605720060204).
131211440120402 is an equidigital number, since it uses as much as digits as its factorization.
131211440120402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65605720060203.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 131211440120402 its reverse (204021044112131), we get a palindrome (335232484232533).
The spelling of 131211440120402 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred forty million, one hundred twenty thousand, four hundred two".
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