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131211444134002 = 265605722067001
BaseRepresentation
bin11101110101011000001011…
…100001001010000001110010
3122012120200200010212122022011
4131311120023201022001302
5114144232014144242002
61143021412202033134
736431466622015621
oct3565301341120162
9565520603778264
10131211444134002
11388985085a1601
12128717a71a87aa
13582a255abc1cb
14245894c5696b8
15102819dd038d7
hex77560b84a072

131211444134002 has 4 divisors (see below), whose sum is σ = 196817166201006. Its totient is φ = 65605722067000.

The previous prime is 131211444133981. The next prime is 131211444134011. The reversal of 131211444134002 is 200431444112131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 120134335857561 + 11077108276441 = 10960581^2 + 3328229^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32802861033499 + ... + 32802861033502.

Almost surely, 2131211444134002 is an apocalyptic number.

131211444134002 is a deficient number, since it is larger than the sum of its proper divisors (65605722067004).

131211444134002 is an equidigital number, since it uses as much as digits as its factorization.

131211444134002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65605722067003.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 131211444134002 its reverse (200431444112131), we get a palindrome (331642888246133).

The spelling of 131211444134002 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred forty-four million, one hundred thirty-four thousand, two".

Divisors: 1 2 65605722067001 131211444134002