Base | Representation |
---|---|
bin | 1011111011110000010110… |
… | …1010111001010001110111 |
3 | 1201110101011101201201222010 |
4 | 2332330011222321101313 |
5 | 3204434224334020043 |
6 | 43523445542335303 |
7 | 2522656032435516 |
oct | 276740552712167 |
9 | 51411141651863 |
10 | 13121220220023 |
11 | 41a9750821213 |
12 | 157ab9212a533 |
13 | 7424308c6566 |
14 | 3350db44267d |
15 | 17b4a681e133 |
hex | bef05ab9477 |
13121220220023 has 4 divisors (see below), whose sum is σ = 17494960293368. Its totient is φ = 8747480146680.
The previous prime is 13121220220021. The next prime is 13121220220057. The reversal of 13121220220023 is 32002202212131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13121220220023 - 21 = 13121220220021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121220220021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186870036668 + ... + 2186870036673.
It is an arithmetic number, because the mean of its divisors is an integer number (4373740073342).
Almost surely, 213121220220023 is an apocalyptic number.
13121220220023 is a deficient number, since it is larger than the sum of its proper divisors (4373740073345).
13121220220023 is an equidigital number, since it uses as much as digits as its factorization.
13121220220023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4373740073344.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 13121220220023 its reverse (32002202212131), we get a palindrome (45123422432154).
The spelling of 13121220220023 in words is "thirteen trillion, one hundred twenty-one billion, two hundred twenty million, two hundred twenty thousand, twenty-three".
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