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13121302512640 = 21057834410937
BaseRepresentation
bin1011111011110000101010…
…0100110100010000000000
31201110101101010120122012211
42332330022210310100000
53204434411420401030
643523502042231504
72522661052060630
oct276741244642000
951411333518184
1013121302512640
1141a9793218943
12157abb57b5594
1374244497a30a
143351083446c0
1517b4adb7712a
hexbef0a934400

13121302512640 has 176 divisors, whose sum is σ = 36405694426752. Its totient is φ = 4444529688576.

The previous prime is 13121302512601. The next prime is 13121302512671. The reversal of 13121302512640 is 4621520312131.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 769252 + ... + 5180188.

Almost surely, 213121302512640 is an apocalyptic number.

13121302512640 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121302512640, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18202847213376).

13121302512640 is an abundant number, since it is smaller than the sum of its proper divisors (23284391914112).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121302512640 is an equidigital number, since it uses as much as digits as its factorization.

13121302512640 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4411052 (or 4411034 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13121302512640 its reverse (4621520312131), we get a palindrome (17742822824771).

The spelling of 13121302512640 in words is "thirteen trillion, one hundred twenty-one billion, three hundred two million, five hundred twelve thousand, six hundred forty".