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131213200000 = 27552231471
BaseRepresentation
bin111101000110011101…
…0101000101010000000
3110112200110210012011011
41322030322220222000
54122211034400000
6140140054130304
712323404540411
oct1721472505200
9415613705134
10131213200000
1150713481263
122151b050994
13c4b133b25c
1464ca673808
15362e60a2ba
hex1e8cea8a80

131213200000 has 192 divisors, whose sum is σ = 328418979840. Its totient is φ = 52214400000.

The previous prime is 131213199983. The next prime is 131213200021. The reversal of 131213200000 is 2312131.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 89199265 + ... + 89200735.

It is an arithmetic number, because the mean of its divisors is an integer number (1710515520).

Almost surely, 2131213200000 is an apocalyptic number.

131213200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131213200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164209489920).

131213200000 is an abundant number, since it is smaller than the sum of its proper divisors (197205779840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131213200000 is an frugal number, since it uses more digits than its factorization.

131213200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1733 (or 1701 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 131213200000 its reverse (2312131), we get a palindrome (131215512131).

The spelling of 131213200000 in words is "one hundred thirty-one billion, two hundred thirteen million, two hundred thousand".