Base | Representation |
---|---|
bin | 11000011100001101… |
… | …00000000101111101 |
3 | 1020212110101121121111 |
4 | 30032012200011331 |
5 | 203333100042404 |
6 | 10010011002021 |
7 | 643106541544 |
oct | 141606400575 |
9 | 36773347544 |
10 | 13121487229 |
11 | 5623812624 |
12 | 2662439311 |
13 | 13115c9836 |
14 | 8c695115b |
15 | 51be4d104 |
hex | 30e1a017d |
13121487229 has 4 divisors (see below), whose sum is σ = 13812091840. Its totient is φ = 12430882620.
The previous prime is 13121487227. The next prime is 13121487283. The reversal of 13121487229 is 92278412131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13121487229 - 21 = 13121487227 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13121487191 and 13121487200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121487221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345302277 + ... + 345302314.
It is an arithmetic number, because the mean of its divisors is an integer number (3453022960).
Almost surely, 213121487229 is an apocalyptic number.
13121487229 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
It is an amenable number.
13121487229 is a deficient number, since it is larger than the sum of its proper divisors (690604611).
13121487229 is an equidigital number, since it uses as much as digits as its factorization.
13121487229 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 690604610.
The product of its digits is 48384, while the sum is 40.
The spelling of 13121487229 in words is "thirteen billion, one hundred twenty-one million, four hundred eighty-seven thousand, two hundred twenty-nine".
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