1312200031 has 4 divisors (see below), whose sum is σ = 1316870064. Its totient is φ = 1307530000.

The previous prime is 1312200013. The next prime is 1312200049. The reversal of 1312200031 is 1300022131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1300022131 = 1699 ⋅765169.

It is an interprime number because it is at equal distance from previous prime (1312200013) and next prime (1312200049).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312200031 is a prime.

It is a super-2 number, since 2×1312200031² = 3443737842712801922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312199984 and 1312200020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312200011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2334595 + ... + 2335156.

It is an arithmetic number, because the mean of its divisors is an integer number (329217516).

Almost surely, 2^1312200031 is an apocalyptic number.

1312200031 is a deficient number, since it is larger than the sum of its proper divisors (4670033).

1312200031 is an equidigital number, since it uses as much as digits as its factorization.

1312200031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4670032.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1312200031 is about 36224.3016633861. The cubic root of 1312200031 is about 1094.7963678245.

Adding to 1312200031 its reverse (1300022131), we get a palindrome (2612222162).

The spelling of 1312200031 in words is "one billion, three hundred twelve million, two hundred thousand, thirty-one".