Base | Representation |
---|---|
bin | 10011000110000101010… |
… | …001111100111110100111 |
3 | 11122110000112212121121001 |
4 | 103012011101330332213 |
5 | 132444341440214343 |
6 | 2442452235334131 |
7 | 163542365220145 |
oct | 23060521747647 |
9 | 4573015777531 |
10 | 1312201101223 |
11 | 466557349121 |
12 | 1923915b1347 |
13 | 96980b1056c |
14 | 47721b94595 |
15 | 2420016b44d |
hex | 1318547cfa7 |
1312201101223 has 4 divisors (see below), whose sum is σ = 1330176458848. Its totient is φ = 1294225743600.
The previous prime is 1312201101209. The next prime is 1312201101227. The reversal of 1312201101223 is 3221011022131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312201101223 - 29 = 1312201100711 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1312201101223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312201101227) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8987678703 + ... + 8987678848.
It is an arithmetic number, because the mean of its divisors is an integer number (332544114712).
Almost surely, 21312201101223 is an apocalyptic number.
1312201101223 is a deficient number, since it is larger than the sum of its proper divisors (17975357625).
1312201101223 is an equidigital number, since it uses as much as digits as its factorization.
1312201101223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17975357624.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1312201101223 its reverse (3221011022131), we get a palindrome (4533212123354).
The spelling of 1312201101223 in words is "one trillion, three hundred twelve billion, two hundred one million, one hundred one thousand, two hundred twenty-three".
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