Base | Representation |
---|---|
bin | 11000011100010001… |
… | …00000011101010011 |
3 | 1020212111101022211220 |
4 | 30032020200131103 |
5 | 203333213404021 |
6 | 10010030140123 |
7 | 643114161462 |
oct | 141610403523 |
9 | 36774338756 |
10 | 13122013011 |
11 | 5624041658 |
12 | 2662651643 |
13 | 1311751c53 |
14 | 8c6a4a9d9 |
15 | 51c003cc6 |
hex | 30e220753 |
13122013011 has 4 divisors (see below), whose sum is σ = 17496017352. Its totient is φ = 8748008672.
The previous prime is 13122013007. The next prime is 13122013027. The reversal of 13122013011 is 11031022131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11031022131 = 3 ⋅3677007377.
It is a cyclic number.
It is not a de Polignac number, because 13122013011 - 22 = 13122013007 is a prime.
It is a super-2 number, since 2×131220130112 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13122013001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187002166 + ... + 2187002171.
It is an arithmetic number, because the mean of its divisors is an integer number (4374004338).
Almost surely, 213122013011 is an apocalyptic number.
13122013011 is a deficient number, since it is larger than the sum of its proper divisors (4374004341).
13122013011 is an equidigital number, since it uses as much as digits as its factorization.
13122013011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4374004340.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 13122013011 its reverse (11031022131), we get a palindrome (24153035142).
The spelling of 13122013011 in words is "thirteen billion, one hundred twenty-two million, thirteen thousand, eleven".
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