Base | Representation |
---|---|
bin | 1011111011110011101000… |
… | …0111110011000110000111 |
3 | 1201110110102201120222011101 |
4 | 2332330322013303012013 |
5 | 3204443030123241403 |
6 | 43524113135520531 |
7 | 2523016606313221 |
oct | 276747207630607 |
9 | 51413381528141 |
10 | 13122100212103 |
11 | 41aa0625282a3 |
12 | 157b198989147 |
13 | 74254100602c |
14 | 335182271411 |
15 | 17b508be771d |
hex | bef3a1f3187 |
13122100212103 has 8 divisors (see below), whose sum is σ = 13172213411136. Its totient is φ = 13071999456000.
The previous prime is 13122100212083. The next prime is 13122100212217. The reversal of 13122100212103 is 30121200122131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13122100212103 - 213 = 13122100203911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122100218103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 994798 + ... + 5218603.
It is an arithmetic number, because the mean of its divisors is an integer number (1646526676392).
Almost surely, 213122100212103 is an apocalyptic number.
13122100212103 is a deficient number, since it is larger than the sum of its proper divisors (50113199033).
13122100212103 is an equidigital number, since it uses as much as digits as its factorization.
13122100212103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6221465.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13122100212103 its reverse (30121200122131), we get a palindrome (43243300334234).
The spelling of 13122100212103 in words is "thirteen trillion, one hundred twenty-two billion, one hundred million, two hundred twelve thousand, one hundred three".
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