Base | Representation |
---|---|
bin | 111101000110101100… |
… | …1001100111110111010 |
3 | 110112201000212022002011 |
4 | 1322031121030332322 |
5 | 4122220112304424 |
6 | 140140542000134 |
7 | 12323532623305 |
oct | 1721531147672 |
9 | 415630768064 |
10 | 131221213114 |
11 | 50717a54672 |
12 | 2152187604a |
13 | c4b2bb5644 |
14 | 64cb75bb3c |
15 | 363018e694 |
hex | 1e8d64cfba |
131221213114 has 4 divisors (see below), whose sum is σ = 196831819674. Its totient is φ = 65610606556.
The previous prime is 131221213111. The next prime is 131221213133. The reversal of 131221213114 is 411312122131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411312122131 = 487 ⋅844583413.
It can be written as a sum of positive squares in only one way, i.e., 129812487025 + 1408726089 = 360295^2 + 37533^2 .
It is a super-2 number, since 2×1312212131142 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131221213111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32805303277 + ... + 32805303280.
Almost surely, 2131221213114 is an apocalyptic number.
131221213114 is a deficient number, since it is larger than the sum of its proper divisors (65610606560).
131221213114 is an equidigital number, since it uses as much as digits as its factorization.
131221213114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65610606559.
The product of its digits is 288, while the sum is 22.
Adding to 131221213114 its reverse (411312122131), we get a palindrome (542533335245).
The spelling of 131221213114 in words is "one hundred thirty-one billion, two hundred twenty-one million, two hundred thirteen thousand, one hundred fourteen".
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