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1312221233131 = 2945249008039
BaseRepresentation
bin10011000110000110011…
…110101111111111101011
311122110001221202102101021
4103012012132233333223
5132444412113430011
62442454235033311
7163543031305564
oct23060636577753
94573057672337
101312221233131
11466567749566
1219239829b837
139698503ba33
144772471516b
1524201ce6471
hex131867affeb

1312221233131 has 4 divisors (see below), whose sum is σ = 1357470241200. Its totient is φ = 1266972225064.

The previous prime is 1312221233101. The next prime is 1312221233143. The reversal of 1312221233131 is 1313321222131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1312221233131 - 221 = 1312219135979 is a prime.

It is a super-2 number, since 2×13122212331312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312221233096 and 1312221233105.

It is not an unprimeable number, because it can be changed into a prime (1312221233101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22624503991 + ... + 22624504048.

It is an arithmetic number, because the mean of its divisors is an integer number (339367560300).

Almost surely, 21312221233131 is an apocalyptic number.

1312221233131 is a deficient number, since it is larger than the sum of its proper divisors (45249008069).

1312221233131 is an equidigital number, since it uses as much as digits as its factorization.

1312221233131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45249008068.

The product of its digits is 1296, while the sum is 25.

Adding to 1312221233131 its reverse (1313321222131), we get a palindrome (2625542455262).

The spelling of 1312221233131 in words is "one trillion, three hundred twelve billion, two hundred twenty-one million, two hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 29 45249008039 1312221233131