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1312222330113 = 3437407443371
BaseRepresentation
bin10011000110000110100…
…010111011110100000001
311122110002000211011011020
4103012012202323310001
5132444412404030423
62442454314340053
7163543043525022
oct23060642736401
94573060734136
101312222330113
11466568328762
1219239872a629
1396985334136
144772491cc49
1524201e614e3
hex131868bbd01

1312222330113 has 4 divisors (see below), whose sum is σ = 1749629773488. Its totient is φ = 874814886740.

The previous prime is 1312222330043. The next prime is 1312222330129. The reversal of 1312222330113 is 3110332222131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312222330113 - 28 = 1312222329857 is a prime.

It is a super-2 number, since 2×13122223301132 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1312222330163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218703721683 + ... + 218703721688.

It is an arithmetic number, because the mean of its divisors is an integer number (437407443372).

Almost surely, 21312222330113 is an apocalyptic number.

It is an amenable number.

1312222330113 is a deficient number, since it is larger than the sum of its proper divisors (437407443375).

1312222330113 is an equidigital number, since it uses as much as digits as its factorization.

1312222330113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437407443374.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1312222330113 its reverse (3110332222131), we get a palindrome (4422554552244).

The spelling of 1312222330113 in words is "one trillion, three hundred twelve billion, two hundred twenty-two million, three hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 437407443371 1312222330113