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1312223200311 = 3437407733437
BaseRepresentation
bin10011000110000110100…
…110010000010000110111
311122110002002110100211210
4103012012212100100313
5132444413114402221
62442454345132503
7163543054111032
oct23060646202067
94573062410753
101312223200311
11466568872531
12192398a8a133
139698557a24a
1447724aa8019
1524202084276
hex13186990437

1312223200311 has 4 divisors (see below), whose sum is σ = 1749630933752. Its totient is φ = 874815466872.

The previous prime is 1312223200261. The next prime is 1312223200319. The reversal of 1312223200311 is 1130023222131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1312223200311 - 215 = 1312223167543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312223200319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218703866716 + ... + 218703866721.

It is an arithmetic number, because the mean of its divisors is an integer number (437407733438).

Almost surely, 21312223200311 is an apocalyptic number.

1312223200311 is a deficient number, since it is larger than the sum of its proper divisors (437407733441).

1312223200311 is an equidigital number, since it uses as much as digits as its factorization.

1312223200311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437407733440.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1312223200311 its reverse (1130023222131), we get a palindrome (2442246422442).

The spelling of 1312223200311 in words is "one trillion, three hundred twelve billion, two hundred twenty-three million, two hundred thousand, three hundred eleven".

Divisors: 1 3 437407733437 1312223200311