13122242044241 has 4 divisors (see below), whose sum is σ = 14315173139184. Its totient is φ = 11929310949300.

The previous prime is 13122242044213. The next prime is 13122242044273. The reversal of 13122242044241 is 14244024222131.

13122242044241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13122242044241 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13122242044198 and 13122242044207.

It is not an unprimeable number, because it can be changed into a prime (13122242044211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596465547455 + ... + 596465547476.

It is an arithmetic number, because the mean of its divisors is an integer number (3578793284796).

Almost surely, 2^{13122242044241} is an apocalyptic number.

13122242044241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13122242044241 is a deficient number, since it is larger than the sum of its proper divisors (1192931094943).

13122242044241 is a wasteful number, since it uses less digits than its factorization.

13122242044241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192931094942.

The product of its (nonzero) digits is 24576, while the sum is 32.

Adding to 13122242044241 its reverse (14244024222131), we get a palindrome (27366266266372).

The spelling of 13122242044241 in words is "thirteen trillion, one hundred twenty-two billion, two hundred forty-two million, forty-four thousand, two hundred forty-one".