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13122302540413 = 111923304533503
BaseRepresentation
bin1011111011110100011000…
…1011100111101001111101
31201110110221211022022102111
42332331012023213221331
53204443433422243123
643524145204254021
72523024614135533
oct276750613475175
951413854268374
1013122302540413
1141aa156760580
12157b2346a1311
13742573bc7021
143351a109c153
1517b51b86190d
hexbef462e7a7d

13122302540413 has 12 divisors (see below), whose sum is σ = 15108327180288. Its totient is φ = 11301504576840.

The previous prime is 13122302540407. The next prime is 13122302540423. The reversal of 13122302540413 is 31404520322131.

It is not a de Polignac number, because 13122302540413 - 213 = 13122302532221 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13122302540423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1652262781 + ... + 1652270722.

It is an arithmetic number, because the mean of its divisors is an integer number (1259027265024).

Almost surely, 213122302540413 is an apocalyptic number.

It is an amenable number.

13122302540413 is a deficient number, since it is larger than the sum of its proper divisors (1986024639875).

13122302540413 is a wasteful number, since it uses less digits than its factorization.

13122302540413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3304533552 (or 3304533533 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13122302540413 its reverse (31404520322131), we get a palindrome (44526822862544).

The spelling of 13122302540413 in words is "thirteen trillion, one hundred twenty-two billion, three hundred two million, five hundred forty thousand, four hundred thirteen".

Divisors: 1 11 19 209 361 3971 3304533503 36349868533 62786136557 690647502127 1192936594583 13122302540413