Base | Representation |
---|---|
bin | 11101110101100010111110… |
… | …010110100101111100101010 |
3 | 122012121210120220001020010020 |
4 | 131311202332112211330222 |
5 | 114144424233302433114 |
6 | 1143031010234101310 |
7 | 36432360056565123 |
oct | 3565427626457452 |
9 | 565553526036106 |
10 | 131223034421034 |
11 | 388a2415a53816 |
12 | 12873aa087a836 |
13 | 582b3820c140a |
14 | 245932b9b504a |
15 | 102862b5e2aa9 |
hex | 7758be5a5f2a |
131223034421034 has 16 divisors (see below), whose sum is σ = 264898835841888. Its totient is φ = 43332216973712.
The previous prime is 131223034421029. The next prime is 131223034421117. The reversal of 131223034421034 is 430124430322131.
It is a junction number, because it is equal to n+sod(n) for n = 131223034420986 and 131223034421004.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102198624297 + ... + 102198625580.
It is an arithmetic number, because the mean of its divisors is an integer number (16556177240118).
Almost surely, 2131223034421034 is an apocalyptic number.
131223034421034 is an abundant number, since it is smaller than the sum of its proper divisors (133675801420854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131223034421034 is a wasteful number, since it uses less digits than its factorization.
131223034421034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204397249989.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 131223034421034 its reverse (430124430322131), we get a palindrome (561347464743165).
The spelling of 131223034421034 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, thirty-four million, four hundred twenty-one thousand, thirty-four".
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