131223034421133 has 4 divisors (see below), whose sum is σ = 174964045894848. Its totient is φ = 87482022947420.

The previous prime is 131223034421117. The next prime is 131223034421147. The reversal of 131223034421133 is 331124430322131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131223034421133 - 2⁴ = 131223034421117 is a prime.

It is a super-2 number, since 2×131223034421133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131223034421094 and 131223034421103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131223034421183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21870505736853 + ... + 21870505736858.

It is an arithmetic number, because the mean of its divisors is an integer number (43741011473712).

Almost surely, 2^{131223034421133} is an apocalyptic number.

It is an amenable number.

131223034421133 is a deficient number, since it is larger than the sum of its proper divisors (43741011473715).

131223034421133 is an equidigital number, since it uses as much as digits as its factorization.

131223034421133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43741011473714.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 131223034421133 its reverse (331124430322131), we get a palindrome (462347464743264).

The spelling of 131223034421133 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, thirty-four million, four hundred twenty-one thousand, one hundred thirty-three".