Base | Representation |
---|---|
bin | 1011111011110100011100… |
… | …1111000010010011010011 |
3 | 1201110111000001120011221021 |
4 | 2332331013033002103103 |
5 | 3204444002433310303 |
6 | 43524151035140311 |
7 | 2523025220302645 |
oct | 276750717022323 |
9 | 51414001504837 |
10 | 13122320213203 |
11 | 41aa165731393 |
12 | 157b23a5a4697 |
13 | 7425777740b6 |
14 | 3351a357c895 |
15 | 17b51d1a2ebd |
hex | bef473c24d3 |
13122320213203 has 4 divisors (see below), whose sum is σ = 13181164698688. Its totient is φ = 13063475727720.
The previous prime is 13122320213201. The next prime is 13122320213269. The reversal of 13122320213203 is 30231202322131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13122320213203 - 21 = 13122320213201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122320213201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29422242408 + ... + 29422242853.
It is an arithmetic number, because the mean of its divisors is an integer number (3295291174672).
Almost surely, 213122320213203 is an apocalyptic number.
13122320213203 is a deficient number, since it is larger than the sum of its proper divisors (58844485485).
13122320213203 is an equidigital number, since it uses as much as digits as its factorization.
13122320213203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58844485484.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13122320213203 its reverse (30231202322131), we get a palindrome (43353522535334).
The spelling of 13122320213203 in words is "thirteen trillion, one hundred twenty-two billion, three hundred twenty million, two hundred thirteen thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •