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13122350500501 = 111192940954591
BaseRepresentation
bin1011111011110100100100…
…0010100100101010010101
31201110111002011112221022001
42332331021002210222111
53204444033212004001
643524154040235301
72523026035606054
oct276751102445225
951414064487261
1013122350500501
1141aa180838710
12157b24876bb31
13742580b19a88
143351a75c439b
1517b520b87001
hexbef490a4a95

13122350500501 has 4 divisors (see below), whose sum is σ = 14315291455104. Its totient is φ = 11929409545900.

The previous prime is 13122350500487. The next prime is 13122350500507. The reversal of 13122350500501 is 10500505322131.

13122350500501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13122350500501 - 27 = 13122350500373 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13122350500501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13122350500507) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596470477285 + ... + 596470477306.

It is an arithmetic number, because the mean of its divisors is an integer number (3578822863776).

Almost surely, 213122350500501 is an apocalyptic number.

13122350500501 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13122350500501 is a deficient number, since it is larger than the sum of its proper divisors (1192940954603).

13122350500501 is a wasteful number, since it uses less digits than its factorization.

13122350500501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192940954602.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 13122350500501 its reverse (10500505322131), we get a palindrome (23622855822632).

The spelling of 13122350500501 in words is "thirteen trillion, one hundred twenty-two billion, three hundred fifty million, five hundred thousand, five hundred one".

Divisors: 1 11 1192940954591 13122350500501