13122412041433 has 8 divisors (see below), whose sum is σ = 13133310766056. Its totient is φ = 13111516070400.

The previous prime is 13122412041341. The next prime is 13122412041449. The reversal of 13122412041433 is 33414021422131.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 260347919049 + 12862064122384 = 510243^2 + 3586372^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13122412041433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13122412041395 and 13122412041404.

It is not an unprimeable number, because it can be changed into a prime (13122412041833) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8902093 + ... + 10270933.

It is an arithmetic number, because the mean of its divisors is an integer number (1641663845757).

Almost surely, 2^{13122412041433} is an apocalyptic number.

It is an amenable number.

13122412041433 is a deficient number, since it is larger than the sum of its proper divisors (10898724623).

13122412041433 is a wasteful number, since it uses less digits than its factorization.

13122412041433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1376795.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13122412041433 its reverse (33414021422131), we get a palindrome (46536433463564).

The spelling of 13122412041433 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twelve million, forty-one thousand, four hundred thirty-three".