Base | Representation |
---|---|
bin | 1011111011110100110010… |
… | …1101100100010111100111 |
3 | 1201110111020110110200020101 |
4 | 2332331030231210113213 |
5 | 3204444144444300033 |
6 | 43524204120444531 |
7 | 2523030414326440 |
oct | 276751455442747 |
9 | 51414213420211 |
10 | 13122412103143 |
11 | 41aa202593692 |
12 | 157b265319747 |
13 | 742590808345 |
14 | 3351b185c2c7 |
15 | 17b5262a497d |
hex | bef4cb645e7 |
13122412103143 has 8 divisors (see below), whose sum is σ = 14997086502912. Its totient is φ = 11247748728216.
The previous prime is 13122412103131. The next prime is 13122412103149. The reversal of 13122412103143 is 34130121422131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13122412103143 - 229 = 13121875232231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122412103149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25255 + ... + 5123032.
It is an arithmetic number, because the mean of its divisors is an integer number (1874635812864).
Almost surely, 213122412103143 is an apocalyptic number.
13122412103143 is a deficient number, since it is larger than the sum of its proper divisors (1874674399769).
13122412103143 is an equidigital number, since it uses as much as digits as its factorization.
13122412103143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5512421.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 13122412103143 its reverse (34130121422131), we get a palindrome (47252533525274).
The spelling of 13122412103143 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twelve million, one hundred three thousand, one hundred forty-three".
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